

Explanation
Vertical component velocity Vy = Usin\(\theta\)
Time to reach maximium height = t
V = USin\(\theta\) — gt
But V at maximum height = O
.-. O = Usin\(\theta\) - gt
Hence, t = \(\frac{U sin \theta}{g}\)
But time for a projectile to reach maximum he is equal to time to return to projection plane
Time of flight T = \(\frac{2Usin \theta}{g}\)


