(a)(i) A machine is a device used to overcome a load at one end by the application of an effort at another end. Examples of simple machine include the screw jack, can opener, pulley system. (ii) M.A. is the ratio of the load (L) to the Effort (E).
\(M.A = \frac{Load}{Effort}\)
V.R. is the ratio of the distance moved by the effort tc the distarice moved by the load (at the same time).
\(V.R = \frac{\text{distance moved by effort}}{\text{distance moved by load}}\)
Efficiency (E) is the ratio of the useful work done by the machine (work output) to the total work put into the machine (work input).
\(Efficiency = \frac{\text{work done on load}}{\text{work done by effort}} \times 100%\)

\(Efficiency = \frac{M.A}{V.R} \times 100%\);
\(Work = Force \times Distance\)
\(Efficiency = \frac{\text{work output}}{\text{work input}} \)
= \(\frac{Load \times \text{distance moved by load}}{Effort \times \text{distance moved by effort}}\)
= \(M.A \times \frac{1}{V.R} \times 100%\)~(b) The efficiency of a simple machine is not 100% because of the work done in overcoming friction.
(c) length of tommy bar. L = 70cm = 0.7m; Pitch = 4.4mm = 0.0044m.
(i) \(V.R = \frac{2\pi L}{pitch} = \frac{2 \pi \times 0.7}{0.0044}\)
= \(2 \times \frac{22}{7} \times \frac{0.7}{44 \times 10^{-4}}\)
\(V.R = 1000\)
(ii) \(Efficiency = \frac{M.A}{V.R} \times 100%\)
\(\frac{80}{100} = \frac{M.A}{1000} \implies M.A = 800\)
(iii) \(M.A = \frac{Load}{Effort}\)
\(Effort = \frac{8000 \times 10}{800} = 100N\)
(iv) Work done = \(\frac{load \times \text{distance moved by load}}{effort \times \text{distance moved by effort}}\)
= \(\frac{8000 \times 10 \times 0.2}{0.8} = 20,000J\)
~(c) length of tommy bar. L = 70cm = 0.7m; Pitch = 4.4mm = 0.0044m.
(i) \(V.R = \frac{2\pi L}{pitch} = \frac{2 \pi \times 0.7}{0.0044}\)
= \(2 \times \frac{22}{7} \times \frac{0.7}{44 \times 10^{-4}}\)
\(V.R = 1000\)
(ii) \(Efficiency = \frac{M.A}{V.R} \times 100%\)
\(\frac{80}{100} = \frac{M.A}{1000} \implies M.A = 800\)
(iii) \(M.A = \frac{Load}{Effort}\)
\(Effort = \frac{8000 \times 10}{800} = 100N\)
(iv) Work done = \(\frac{load \times \text{distance moved by load}}{effort \times \text{distance moved by effort}}\)
= \(\frac{8000 \times 10 \times 0.2}{0.8} = 20,000J\)
