

Explanation
(a)(i) Electric potential is the work done in moving a unit positive charge from infinity to a point in an electric field. H is measured in volts or J/C.
(ii) Electric potential energy is the work done or energy required to move a charged particle from infinity to a point in an electric field. The unit is Joules.
(ii) Electric potential unit is in volts v. Electric potential energy is measured in Joules (J)

(b) (i) Electric field intensity E = \(\frac{Q}{4 \pi \varepsilon_or^2}\)
(ii) Electric potential V = \(\frac{Q}{4 \pi \varepsilon_or}\)
(iii) \(\frac{E}{v} = \frac{I}{r}\) OR E = \(\frac{Y}{4 \pi \varepsilon_o r}\)

(c) E = \(\frac{v}{d} = \frac{5 \times 10^4}{5 \times 10^{-3}} = 10^7 v/m\)
(ii) F = qE = 1.6 x 10\(^{-19}\) x 10\(^{7}\) = 1.6 x 10\(^{-12}\) N
(iii) F = ma
a = \(\frac{F}{m}\) = \(\frac{1.6 \times 10^{-12}}{9.1 \times 10^{-31}}\)
= 1.76 x 10\(^{18}\) m/s\(^2\)

