

Explanation
(a)(i) Electric field intensity = Electric force per unit charge OR As negative potential i.e.E = \(\frac{-V}{d}\)
OR E = \(\frac{F}{Q}\). where F is the force,

Q is the charge and E electric field intensity.
(ii) Electric potential =- work done per unit charge to bring a (positive) charge from infinity to a point in an electric field.

(b)


(c) (i) A dielectric substance is any insulating material placed between the plates of a capacitor



(ii) Factors
Effect on capacitor



common area of plates
Distance between plates
Nature of dielectric 


capacitance increases with area
capacitance decreased with increasing distance
capacitance increases with dielectric constant





C = \(\frac{KE_oA}{A}\)
(iii) C\(_{2.3}\) = C\(_2\) + C\(_3\) = 20 + 20 = 40\(\mu\) F
\(\frac{1}{C_T} = \frac{1}{C_{2.3}} + \frac{1}{C_1}\)
\(C_T = \frac{\frac{C_{2.3} \times C_1}{C_2.3 + C_1} = \frac{40 \times 40}{40 \times 40}\)
= 20\(\mu F\)

