

Explanation
(a) Uniform acceleration is the constant time rate of increase in velocity.
(b) (i) Horizontal Force;
Forward force - Thrust
backward force - Frictional force
(ii) Vertical Force
Upward force - Normal reaction.
Downward force - Weight of the car.

(c)




(ii) (\(\lambda\)) Total distance
= Area of trapezium OABC
= \(\frac{1}{2}\)[AB + OC] AD
= \(\frac{1}{2}\)[60+30] x 25
=1125m
(\(\beta\)) Deceleration = slope of BC
= \(\frac{BE}{CE} = \frac{25}{10}\)
= 25m/s\(^2\)

(d) Work done = \(\frac{1}{2}\)Fe
= \(\frac{1}{2}\) x 12 x \(\frac{0.5}{100}\)J
= 0.03J

